SOLUTION: Five times the second of three consecutive odd integers is twelve less than three times the sum of the first and third integers. Find the largest odd integer.
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Question 902281: Five times the second of three consecutive odd integers is twelve less than three times the sum of the first and third integers. Find the largest odd integer.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)
5x = 3((x-2) + (x+2)) + 12
5x = 3(3x) + 12
5x = 9x + 12
-4x = 12
x = -3
The integers are -5, -3, and -1.
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