SOLUTION: Find two consecutive odd intgers such that the smaller one is sixteen more than one third the larger.

Question 899069: Find two consecutive odd intgers such that the smaller one is sixteen more than one third the larger.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find two consecutive odd intgers such that the smaller one is sixteen more than one third the larger.
------
1st: 2x-1
2nd: 2x+1
-----
Equation:
2x-1 = (1/3)(2x+1) + 16
----------------------
Multiply thru by 3 to get rid of the fraction:
6x -3 = (2x+1) + 48
4x-3 = 49
4x = 52
x = 13
---
1st: 2x-1 = 25
2nd: 2x+1 = 27
------------------
Cheers,
Stan H.
------------------
RELATED QUESTIONS
Find two consecutive odd integers such as the smaller one is 12 more than one-third the... (answered by CubeyThePenguin)

Find two consecutive odd interegers such that the smaller one is ten more than one-fifth... (answered by algebrahouse.com)

two consecutive odd integers are such, that one-third the smaller one is greater than... (answered by checkley79)

Two consecutive odd integers are such that one third the smaller one is greater than... (answered by josgarithmetic,MathTherapy)

Find two consecutive odd integers such that the square of the larger one is 25 more than... (answered by solver91311,imurbabiigurl)

find two consecutive odd intergers such that twice the larger is 17 more than the... (answered by checkley71)

Find two consecutive odd intergers such that twice the larger is 17 more than the... (answered by stanbon)

Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by QH)

Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by mananth)