SOLUTION: Eight times the sum of three consecutive odd integers is 210 more than ten times the middle integer. Find the integers.
8(x)+(x+2)+(x+4)=210+10(x+2)
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Question 896144: Eight times the sum of three consecutive odd integers is 210 more than ten times the middle integer. Find the integers.
8(x)+(x+2)+(x+4)=210+10(x+2)
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
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8[(x)+(x+2)+(x+4)]=210+10(x+2)
x=13
x+2=15
x+3=17
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