SOLUTION: Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.

Question 891190: Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.
Answer by harpazo(655) (Show Source): You can put this solution on YOUR website!
I decided to do it again.
Being consecutive even numbers, we need to add 2 to the previous number.
Assign variables :
Let x = first consecutive even
Let x + 2 = second consecutive even
Let x + 4 = third consecutive even
4x = 6 + 2(x+4)
4x = 6 + 2x + 8
4x = 2x + 14
4x - 2x = 14
2x = 14
x = 14/2
x = 7
The numbers are 7, 9, and 11.
As you can see, the numbers are odd not even. There could be a typo in your original question. There is no way we can get three consecutive even integers from this question. We get three consecutive odd integers.

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