SOLUTION: Find three consecutive odd integers such that the sum of the second and the third is equal to four times the first.

Question 890431: Find three consecutive odd integers such that the sum of the second and the third is equal to four times the first.
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
B = A-2 (they are consecutive odd, so 2 apart)
C = A-4
B+C = 4A
Substitute the known values of B & C from the top equations into the bottom equation.
B+C = 4A
(a-2) + (a-4) = 4A
2A - 6 = 4A
Subtract 2A from each side
-6 = 2A
Divide each side by 2
-3 = A
Therefore, B = -5 and C = -7

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