SOLUTION: Find three consecutive intergers whose sum is the square of 6.

Question 885929: Find three consecutive intergers whose sum is the square of 6.

Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
A + B + C =
A + B + C = 36
B = A-1 (consecutive)
C = A-2
Substitute the value of B and C into the first equation.
A + B + C = 36
A + (A-1) + (A-2) = 36
3A - 3 = 36
Add 3 to each side
3A = 39
Divide each side by 3
A = 13
Since they're consecutive, and the largest number is 13, the others are 12 and 11.
11 + 12 + 13 = 36
.
Another way would be to divide 36 by 3 to find the middle number.
36/3 = 12
One number is one more, one number is one less than 12.
RELATED QUESTIONS
Find three consecutive odd intergers whose sum is 105. (answered by elima)

find three consecutive intergers whose sum is... (answered by kapilsinghi)

Find three consecutive intergers whose sum is... (answered by joyofmath,stanbon)

Find three consecutive odd intergers whose sum is... (answered by checkley71)

three consecutive intergers whose sum is... (answered by oscargut)

The sum of three consecutive even intergers is 54. Find all three... (answered by Alan3354)

The sum of three consecutive odd intergers is 24 more than the largest of the three... (answered by lwsshak3)

What is the steps to "find three consecutive integers whose sum is the square of... (answered by scott8148)

I'm Very confused on these types of questions : Find the three largest consecutive... (answered by ichigo449)