SOLUTION: How do you find two consecutive odd integers whose product is 36?

Question 879728: How do you find two consecutive odd integers whose product is 36?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
n (n+2)= 36
n^2 + 2n - 36 = 0 Not going to work..solution does not yield an Integer.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=148 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 5.08276253029822, -7.08276253029822. Here's your graph:

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