SOLUTION: How to do:
"Find two consecutive positive integers such that the sum of the square of the first two is 45 larger than the square or the third."
Algebra.Com
Question 878467: How to do:
"Find two consecutive positive integers such that the sum of the square of the first two is 45 larger than the square or the third."
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
"Find two consecutive positive integers such that the sum of the square of the first two is 45 larger than the square or the third."
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For 2 integers, there is no third.
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