SOLUTION: Find two consecutive integers such that twice the smaller is two more than the larger
Algebra.Com
Question 877258: Find two consecutive integers such that twice the smaller is two more than the larger
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: x, (x+1)
2x = (x+1) + 2
2x = x+3
x = 3
The integers are 3 and 4.
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