SOLUTION: find two consecutive integers such that 3 times the first integer is 27 less than 6 times the second.

SOLUTION: find two consecutive integers such that 3 times the first integer is 27 less than 6 times the second.

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Question 876818: find two consecutive integers such that 3 times the first integer is 27 less than 6 times the second.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: x, (x+1)

3x = 6(x+1) - 27
3x = 6x-21
-3x = -21
x = 7

The integers are 7 and 8.
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