SOLUTION: what is larger of two consecutive integers such that the sum of squares is 340?
Algebra.Com
Question 875698: what is larger of two consecutive integers such that the sum of squares is 340?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: x, (x+1)
x^2 + (x+1)^2 = 340
x^2 + x^2 + 2x + 1 = 340
2x^2 + 2x - 339 = 0
This equation has no integer solutions.
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