SOLUTION: find three consecutive odd integers such that the sum of all three is 42 less than the product of the larger two

Question 865115: find three consecutive odd integers such that the sum of all three is 42 less than the product of the larger two
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Let's call those numbers , , and .
(Those are 3 numbers, with each greater than the one before by 2.
The approach could be the same for a problem involving 3 consecutive even numbers.
For this problem, when we solve for , needs to be an odd number.
If we found a value for is the sum of all three consecutive odd integers.
is the product of the larger two consecutive odd integers.
The problem states that
or .

--> --> -->
That last equation is easy to solve by factoring:
--> --> --> .
Since we are expecting to be an odd integer, ,
and the three consecutive odd integers are
, , and .

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