SOLUTION: sum of four consecutive integers is 686, then what is the sum of four previous consecutive integers ?

Question 862770: sum of four consecutive integers is 686, then what is the sum of four previous consecutive integers ?

Found 2 solutions by Alan3354, ankor@dixie-net.com:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
sum of four consecutive integers is 686, then what is the sum of four previous consecutive integers ?
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n + n+1 + n+2 + n+3 = 686
n-1 + n-2 + n-3 + n-4 = 686 - 16 = 670
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
sum of four consecutive integers is 686, then what is the sum of four previous consecutive integers ?
:
Find the first of the 4 integers that add up to 686
n+(n+1)+(n+2)+(n+3) = 686
4n + 6 = 686
4n = 680
n = 680/4
n = 170
then the previous four:
169+168+167+166 = 670
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