SOLUTION: It would be greatly appreciated if you would be able to help me with:
The sum of squares of two positive consecutive odd integers is 74. Find the integers.
I've made an at
Algebra.Com
Question 859573: It would be greatly appreciated if you would be able to help me with:
The sum of squares of two positive consecutive odd integers is 74. Find the integers.
I've made an attempt at:
(x^2)+(x+2)74
Thanks for your help!
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
let x be the first odd integer, then x+2 is the next consecutive odd integer
(x^2) + (x+2)^2 = 74
x^2 + x^2 + 4x +4 = 74
2x^2 + 4x - 70 = 0
(2x-10)*(x+7) = 0
we have two solution sets
x = 5 or -7
our solution sets are
5, 7 or -7, -5
check the answers
5^2 + 7^2 = 25 + 49 = 74
(-7)^2 + (-5)^2 = 49 + 25 = 74
our answers check :-)
RELATED QUESTIONS
It would be greatly appreciated if you are able to breakdown this problem to me:
Julie (answered by stanbon)
It would be greatly appreciated if you would be able to help me with:
Solve the... (answered by josgarithmetic)
It would be greatly appreciated if you would be able to help me with:
Find three... (answered by Awesom3guy)
It would be greatly appreciated if you would be able to help me with:
√70 ÷... (answered by jim_thompson5910)
It would be greatly appreciated if you would be able to help me with:
Use the... (answered by ewatrrr)
Please help me with this question!!! I have NO CLUE what i am doing!! Here is the... (answered by Earlsdon)
If Y is the first of two consecutive odd integers, express the difference of 20 and the... (answered by CubeyThePenguin)
Could you please tell me how I would solve this question?:The sum of the squares of two... (answered by stanbon)
How's it going? I was wondering if you would be able to assist me please, as I am stuck... (answered by bucky,chitra)