Hi,

 three consecutive, positive, even integers: (x),(x+2),(x+4)  Yes!

Question States***product of the second and the third is 80.

(x+2)(x+4)=80 

x^2 + 6x - 72 = 0

(x  + 12)(x- 6) = 0,  x = 6    (tossing out negative solution)

the three consecutive, positive, even integers are:  6, 8, 10 

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
 , , 

are the consecutive even integers

-------------------------------

The product of the second and the third is 80







Complete the square:









Take the square root of both sides









The numbers are 6, 8, and 10 

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