SOLUTION: How do I break this down:
Two consecutive negative integers are multiplied together. To this product is added the sum of the integer. If the result equals 41, determine the intege
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Question 859388: How do I break this down:
Two consecutive negative integers are multiplied together. To this product is added the sum of the integer. If the result equals 41, determine the integers.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = smallest integer
x(x+1) + (x + (x+1)) = 41
x^2 + x + 2x + 1 = 41
x^2 + 3x - 40 = 0
(x + 8)(x - 5) = 0
x = -8, x = 5
x is negative, so the integers are -8 and -7.
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