SOLUTION: find three consecutive even integers such that the product of the two smaller exceeds the largest by 38.

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Question 858360: find three consecutive even integers such that the product of the two smaller exceeds the largest by 38.

Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

(x-2)(x) = x+2 + 38
x^2 - 2x = x + 40
x^2 - 3x - 40 = 0
(x - 8)(x + 5) = 0
x = 8 or x = -5

x has to be even, so the integers are 6, 8, and 10.

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