SOLUTION: One positive integer is four times another, a third integer is six more than the smaller of the two. The sum of the three integers is equal to the smallest integer plus 46. What ar

Question 857468: One positive integer is four times another, a third integer is six more than the smaller of the two. The sum of the three integers is equal to the smallest integer plus 46. What are the integers?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = 4y
z = x + 6
x + y + z = x + 46

x + y + z = x + 46
y + z = 46
x/4 + z = 46 (eqn 1)
-x + z = 6 (eqn 2)

Subtract eqn 2 from eqn 1.

x/4 + z = 46
x - z = -6
-------------
5x/4 = 40 ---> x = 32

The integers are (x, y, z) = (32, 8, 38).
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