SOLUTION: The product of two consecutive odd integers is 25 less than 7 times their sum.

Algebra.Com
Question 856597: The product of two consecutive odd integers is 25 less than 7 times their sum.
Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
consecutive odd integers: x, (x+1)

x(x+1) = 7(x + (x+1)) - 25
x^2 + x = 7(2x+1) - 25
x^2 + x = 14x - 18
x^2 - 13x + 18 = 0


This equation has no integer solutions.

RELATED QUESTIONS

the product of two consecutive odd integers is less than 5 times their sum (answered by DrBeeee)
The product of two consecutive odd integers is 1 less than four times their sum. Find... (answered by RAY100)
The product of two consecutive odd integers is 1 less than four times their sum. Find... (answered by drj)
The product of two consecutive odd integers is 57 less than 9 times their sum. Find the... (answered by CubeyThePenguin,josgarithmetic)
the product of two consecutive integers is 25 less than 5 times their... (answered by macston)
the product of two consecutive positive odd integers is one less than three times their... (answered by mananth)
The product of two consecutive positive odd integers is one less than three times their... (answered by Deina)
The product of two positive consecutive odd integers is 1 less than 5 times their sum.... (answered by KMST)
product of two consecutive, odd, positive, integers is one less than 5 times their... (answered by solver91311)