SOLUTION: find 3 consecutive odd integers such the sum of all three is 6 less than the product of the smaller two

SOLUTION: find 3 consecutive odd integers such the sum of all three is 6 less than the product of the smaller two

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Question 856262: find 3 consecutive odd integers such the sum of all three is 6 less than the product of the smaller two
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2) + x + (x+2) = (x-2)(x) - 6
3x = x^2 - 2x - 6
0 = x^2 - 5x - 6
0 = (x-2)(x-3)
x = 2, x = 3

x must be odd, so the integers are 1, 3, and 5.
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