SOLUTION: The product of two consecutive even integers is 76 less than 10 times their sum. Find the two integers.
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Question 855874: The product of two consecutive even integers is 76 less than 10 times their sum. Find the two integers.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive even integers: x, (x+2)
x(x+2) = 10(x + (x+2)) - 76
x^2 + 2x = 10(2x+2) - 76
x^2 + 2x = 20x - 56
x^2 - 18x + 56 = 0
(x - 4)(x - 14) = 0
The integers could be 4 and 6 or 14 and 16.
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