SOLUTION: Find the dimensions of the rectangle whose width is 8cm less than its length and whose area is 20 cm^2.

SOLUTION: Find the dimensions of the rectangle whose width is 8cm less than its length and whose area is 20 cm^2.

Algebra.Com

Question 854421: Find the dimensions of the rectangle whose width is 8cm less than its length and whose area is 20 cm^2.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
area = width * length

20 = (L)(L - 8)
20 = L^2 - 8L
0 = L^2 - 8L - 20
0 = (L - 10)(L + 2)

Distance is positive, so the rectangle is 10 cm long and 2 cm wide.
RELATED QUESTIONS
the length of a rectangle is 8cm less than three times its width. its area is 35 square... (answered by josgarithmetic)

Find the dimensions of a rectangle whose width is 7 miles less than half its length and... (answered by checkley77)

Find the dimensions of a rectangle whose width is 6 miles less than its length, and whose (answered by mananth)

Find the dimensions of a rectangle whose width is 4 miles less than its length, and whose (answered by LisaDrapeau)

find the dimensions of a rectangle whose width is 3 miles less than its length and whose... (answered by amarjeeth123)

Find the dimensions of a rectangle whose width is 6 miles less than its length and whose... (answered by Cromlix)

Find the dimensions of a rectangle whose width is 11 meters less than its length, and... (answered by Boreal,MathTherapy)

Find the dimensions of a rectangle whose width is 8 miles less than its length and whose... (answered by Alan3354)

Find the dimensions of a rectangle whose width is 1 inches less than half its length an... (answered by CubeyThePenguin)