SOLUTION: find three consecutive integers such that the difference of the squares of the least and the greatest is 96

Question 854418: find three consecutive integers such that the difference of the squares of the least and the greatest is 96
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find three consecutive integers such that the difference of the squares of the least and the greatest is 96
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1st: x-1
2nd: x
3rd: x+1
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Equation:
(x-1)^2-(x+1)^2 = 96
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x^2 -2x + 1 - (x^2 +2x + 1) = 96
-4x = 96
x = -24
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1st: -25
2nd: -24
3rd: -23
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Cheers,
Stan H.
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