SOLUTION: Find three consecutive positive even integers such that the sum of the squares of the first and second integers is equal to the square of the third integer plus 48. How do I set t

Algebra.Com
Question 852797: Find three consecutive positive even integers such that the sum of the squares of the first and second integers is equal to the square of the third integer plus 48. How do I set this up?
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
x^2+(x+2)^2=(x+4)^2+48
2x^2+4x+4 = x^2+8x+64
x^2-4x-60 = 0
x = -6 reject as extraneous negative root
x = 10
10 12 14
check
100+144=196+48
ok

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