SOLUTION: Please help me solve this Three consecutive odd positive integers are such that the squares of the first two integers is greater than the square of the third by 65. Find the int

Question 850321: Please help me solve this
Three consecutive odd positive integers are such that the squares of the first two integers is greater than the square of the third by 65. Find the integers.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2)^2 + x^2 = (x+2)^2 + 65
x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 + 65
2x^2 - 4x + 4 = x^2 + 4x + 69
x^2 - 8x - 65 = 0
(x - 13)(x + 5) = 0
x = 13, x = -5

x is positive, so the integers are 11, 13, and 15.
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