SOLUTION: The sum of three integers is 345. the first and second integer exceeds the third by 77. The third integer is 38 less than the first. find the three integers

Question 847820: The sum of three integers is 345. the first and second integer exceeds the third by 77. The third integer is 38 less than the first. find the three integers
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x + y + z = 345
x + y = z + 77
z = x - 38

Substitute the second equation into the first.

(x + y) + z = 345
z + 77 + z = 345
2z = 268
z = 134

134 = x - 38 ----> x = 172

172 + y + 134 = 345
y = 39

integers: (x, y, z) = (172, 39, 134)
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