SOLUTION: two consecutive odd numbers are chosen so that one third of the smaller exceeds one seventh of the larger by 6. find the numbers.

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Question 844234: two consecutive odd numbers are chosen so that one third of the smaller exceeds one seventh of the larger by 6. find the numbers.

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Call the smaller number
The larger number will be

-----------------------------

Multiply both sides by




The consecutive odd numbers are 33 and 35
check:


Multiply both sides by



OK

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