Hi,
three consecutive integers:, ,
Question states***
4 times the third is 51 less than 3 times the sum of the first and second integers.
***4(x+2) = 3[x + (x+1)] -51 | Solving for x
4x + 8 = 3(2x+1) - 51
4x + 8 = 6x + 3 - 51
56 = 2x
28 = x , the first Integer. The third integer is
CHECKING our answer***
120 = 120
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