SOLUTION: The product of two consecutive integers is 18 more than the square of the smaller number. Find the integers.... I can't figure out how to use algebra in order to solve this. Thank
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Question 837625: The product of two consecutive integers is 18 more than the square of the smaller number. Find the integers.... I can't figure out how to use algebra in order to solve this. Thank you for your help in advance!
Found 2 solutions by richard1234, mananth:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Let x, x+1 be the integers. Then  = 18 + x^2 \Rightarrow x^2 + x = 18 + x^2 \Rightarrow x = 18)
, so the integers are 18 and 19.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the integers be x and (x+1)
x(x+1) = x^2+18
x^2+x=x^2+18
x=18
so the integers are 18,19
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