SOLUTION: find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 46.

SOLUTION: find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 46.

Algebra.Com

Question 836050: find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 46.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2) + 2(x) + 3(x+2) = 46
x-2 + 2x + 3x + 6 = 46
6x + 4 = 46
6x = 42
x = 7

The integers are 5, 7, and 9.
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