SOLUTION: Three consecutive odd integers such that the sum of the first two is equal to eleven more than three times the third
Algebra.Com
Question 835789: Three consecutive odd integers such that the sum of the first two is equal to eleven more than three times the third
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)
(x-2) + x = 11 + 3(x+2)
2x - 2 = 3x + 17
-19 = x
The integers are -21, -19, and -17.
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