SOLUTION: two consecutive odd integers is equal to 27 plus 6 times the sum of the new integers

SOLUTION: two consecutive odd integers is equal to 27 plus 6 times the sum of the new integers

Algebra.Com

Question 835351: two consecutive odd integers is equal to 27 plus 6 times the sum of the new integers
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: x, (x+2)

x + (x+2) = 27 + 6(x + (x+2))
2x + 2 = 27 + 6(2x+2)
2x - 25 = 12x + 12
-37 = 10x

The solutions are not integers.
RELATED QUESTIONS
The product of two consecutive odd integers is equal to 27 plus six times the sum of the... (answered by ikleyn)

The product of two consecutive odd integers is equal to 27 plus six times the sum of the... (answered by josgarithmetic)

Five times the greatest of three consecutive even integers is equal to twice the sum of... (answered by elima)

The sum of three consecutive odd integers is... (answered by Paul)

find the product of two consecutive positive odd integers is equal to 1 less than seven... (answered by Fombitz)

Find three consecutive odd integers such that four times the middle integer is equal to... (answered by solver91311,math-vortex)

Find three consecutive odd integers such that the sum of the first two plus three times... (answered by algebrapro18)

Find 5 consecutive odd integers if 6 times the second plus twice the third is equal to... (answered by TimothyLamb)

Find two consecutive odd integers in which the sum is equal to one or more than three... (answered by drj)