SOLUTION: a square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 52 square feet, find the lengths of the sides of the poste
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Question 832385: a square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 52 square feet, find the lengths of the sides of the poster and sign.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x^2 - (x-2)^2 = 52
x^2 - (x^2 - 4x + 4) = 52
4x - 4 = 52
4x = 56
x = 14
poster side length = 12 ft
sign side length = 14 ft
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