SOLUTION: Find 3 consective odd integers such that 8 more than twice the first integer is equal to 19 less than three times the third integer.
Algebra.Com
Question 829124: Find 3 consective odd integers such that 8 more than twice the first integer is equal to 19 less than three times the third integer.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)
8 + 2(x-2) = 3(x+2) - 19
2x + 4 = 3x - 13
17 = x
The integers are 15, 17, and 19.
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