SOLUTION: 3 consecutive odd integers such that two times the sum of all three is nine less than the product of the first and second integer

SOLUTION: 3 consecutive odd integers such that two times the sum of all three is nine less than the product of the first and second integer

Algebra.Com

Question 828982: 3 consecutive odd integers such that two times the sum of all three is nine less than the product of the first and second integer
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

2((x-2) + x + (x+2)) = (x-2)(x) - 9
2(3x) = x^2 - 2x - 9
6x = x^2 - 2x - 9
0 = x^2 - 8x - 9
0 = (x - 9)(x + 1)
x = 9 or x = -1

The integers could be {7, 9, 11} or {-3, -1, 1}.
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