SOLUTION: five times the second of three consecutive even integers is six more than twice the sum of the first and third integers. write an equation, and find the three integers
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Question 828705: five times the second of three consecutive even integers is six more than twice the sum of the first and third integers. write an equation, and find the three integers
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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z = x + 4
y = x + 2
5y = 2(x + z) + 6
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put the system of linear equations into standard form:
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x - z = -4
x - y = -2
5y = 2x + 2z + 6
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x - z = -4
x - y = -2
2x - 5y + 2z = -6
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 4
y = 6
z = 8
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system matrix
1 0 -1
1 -1 0
2 -5 2
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inverse of system matrix
-2 5 -1
-2 4 -1
-3 5 -1
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determinant of system matrix = 1
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Solve and graph linear equations:
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---
Solve quadratic equations, quadratic formula:
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---
Solve systems of linear equations up to 6-equations 6-variables:
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