SOLUTION: find three consecutive even integer such that three times the first equals the sum of the other two.

Question 826194: find three consecutive even integer such that three times the first equals the sum of the other two.
Answer by Seutip(231) (Show Source): You can put this solution on YOUR website!
Let x - be the first integer
x+2 - be the second integer
x+4 - be the third integer
since they are consecutive even we add 2, each. :)
3(x) = x+2 + x+4 (This is how you translate it to mathematical equation.
3x = 2x+6
x=6

x = 6
x+2 = 6+2 = 8
x+4 = 6+4 = 10
So the three consecutive integers are
6, 8 and 10 :)
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