SOLUTION: Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third.

SOLUTION: Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third.

Algebra.Com

Question 823138: Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive positive integers: (x-1), x, (x+1)

(x-1)(x) = 11(x+1) - 22
x^2 - x = 11x - 11
x^2 - 12x + 11 = 0
(x - 11)(x - 1) = 0

The integers could be {0, 1, 2} or {10, 11, 12}.
RELATED QUESTIONS
Find three consecutive positive integers such that the product of the first two is 22... (answered by stanbon)

find three consecutive positive integers such that the product of the first two is 22... (answered by CubeyThePenguin)

Find three consecutive positive even integers such that the product of the first and... (answered by checkley75)

Find three consecutive positive odd integers such that the product of the first and the... (answered by CubeyThePenguin)

Find three consecutive positive odd integers such that the product of the first and the... (answered by ankor@dixie-net.com)

find three consecutive positive integers such that the product of the first and third one (answered by CubeyThePenguin)

Three consecutive even integers are such that the product of the first two is 6 less than (answered by tutor_paul)

Three consecutive even integers are such that the product of the first two is 6 less than (answered by nyc_function)

Find three consecutive positive odd integers such that the product of the first two is... (answered by ankor@dixie-net.com)