SOLUTION: Find two positive even integers whose product is 48
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Question 822808: Find two positive even integers whose product is 48
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let x be the first integer.
So x+2 is the next consecutive even integer
x*(x+2) = 48
x^2 + 2x = 48
x^2 + 2x - 48 = 0
(x+8)(x-6) = 0
x+8 = 0 or x-6 = 0
x = -8 or x = 6
Since we only want positive even integers, this means that we toss out x = -8 and focus on x = 6
x = 6 ----> x+2 = 6+2 = 8
Therefore, the two numbers are 6 and 8
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find two positive even integers whose product is 48
------------
2*24
4*12
6*8
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