SOLUTION: find three consecutive integers such that 5 more than the sum of the first and second is 72

Algebra.Com
Question 821028: find three consecutive integers such that 5 more than the sum of the first and second is 72
Answer by TimothyLamb(4379)   (Show Source): You can put this solution on YOUR website!
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z = x + 2
y = x + 1
x + y + 5 = 72
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put the system of linear equations into standard form
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x - z = -2
x - y = -1
x + y = 67
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https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x= 33
y= 34
z= 35
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