SOLUTION: Find three consecutive odd positive integers such that two times the sum of all three is seven more than the product of the first and second integers.

SOLUTION: Find three consecutive odd positive integers such that two times the sum of all three is seven more than the product of the first and second integers.

Algebra.Com

Question 814853: Find three consecutive odd positive integers such that two times the sum of all three is seven more than the product of the first and second integers.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let the integers be x, x+2, x+4.
2(x+x+2+x+4)=x(x+2)+7
2(3x+6)=x^2+2x+7
6x+12=...
x^2-4x-5=0
(x-5)(x+1)=0
x=5
x+2=7
x+4=9
.
Ed
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