SOLUTION: Find three consecutive numbers even integers such that three times the first plus six times the second is equal to ten times the second.

SOLUTION: Find three consecutive numbers even integers such that three times the first plus six times the second is equal to ten times the second.

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Question 813818: Find three consecutive numbers even integers such that three times the first plus six times the second is equal to ten times the second.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

3(x-2) + 6x = 10x
3x - 6 + 6x = 10x
9x - 6 = 10x
-6 = x

The integers are -8, -6, and -4.
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