SOLUTION: Find three consecutive positive integers such that the product of rhe first and the third is 29 more than the second.

SOLUTION: Find three consecutive positive integers such that the product of rhe first and the third is 29 more than the second.

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Question 813100: Find three consecutive positive integers such that the product of rhe first and the third is 29 more than the second.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

(x-1)(x+1) = x + 29
x^2 - 1 = x + 29
x^2 - x - 30 = 0
(x - 6)(x + 5) = 0
x = 6, x = -5

x is positive, so the integers are 5, 6, and 7.
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