SOLUTION: the product of two consecutive odd integers is fourteen more than three times the larger integer

Question 812277: the product of two consecutive odd integers is fourteen more than three times the larger integer
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
j = i + 2
i = j - 2
ij = 3j + 14
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ij = 3j + 14
(j - 2)j = 3j + 14
jj - 2j = 3j + 14
jj - 5j - 14 = 0
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the above quadratic equation is in standard form, with a=1, b=-5, and c=-14
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to solve the above equation using the quadratic formula, plug this:
1 -5 -14
into this: https://sooeet.com/math/quadratic-equation-solver.php
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Answer 1:
the roots (x-intercepts) of the above quadratic equation are:
j = 7
j = -2
-2 is not an odd number, so the only valid root is j = 7
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Answer:
the two consecutive odd integers are: 5, 7
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