SOLUTION: the sum of four consecutive odd numbers is 128. Then the smallest number is?

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Question 807894: the sum of four consecutive odd numbers is 128. Then the smallest number is?

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let x be an integer

So 2x is always even

Forcing 2x + 1 to always be odd

The next odd number after that is (2x+1)+2 = 2x + 3

The next odd number after that is (2x+3)+2 = 2x + 5

The next odd number after that is (2x+5)+2 = 2x + 7


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Add up the four integers. Then set this sum equal to 128

(2x+1)+(2x+3)+(2x+5)+(2x+7) = 128

2x+1+2x+3+2x+5+2x+7 = 128

8x+16 = 128

8x = 128-16

8x = 112

x = 112/8

x = 14

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Since x = 14, we know

2x+1 = 2*14 + 1 = 29

2x+3 = 2*14 + 3 = 31

2x+5 = 2*14 + 5 = 33

2x+7 = 2*14 + 7 = 35


So the four consecutive odd integers are: 29, 31, 33, 35

The smallest number is 29

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