SOLUTION: find two consecutive numbers such that 3 time the second exceeds twice the first by 57

SOLUTION: find two consecutive numbers such that 3 time the second exceeds twice the first by 57

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Question 807421: find two consecutive numbers such that 3 time the second exceeds twice the first by 57
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive numbers: x, (x+1)

3(x+1) = 2x + 57
3x + 3 = 2x + 57
x = 54

The numbers are 54 and 55.
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