SOLUTION: Find four consecutive even integers such that four times the greatest is 36 more than the sum of the other three.

SOLUTION: Find four consecutive even integers such that four times the greatest is 36 more than the sum of the other three.

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Question 802267: Find four consecutive even integers such that four times the greatest is 36 more than the sum of the other three.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive even integers: x, (x+2), (x+4), (x+6)

4(x+6) = 36 + (x + (x+2) + (x+4))
4x + 24 = 3x + 6 + 36
x = 18

integers: 18, 20, 22, 24
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