SOLUTION: Find 3 consecutive even integers such that of the sum of the smallest and the second is 5 more than 1/3 of the largest.
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Question 800131
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Find 3 consecutive even integers such that of the sum of the smallest and the second is 5 more than 1/3 of the largest.
Answer by
CubeyThePenguin(3113)
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consecutive even integers: (x-2), x, (x+2)
(x-2) + x = (x+2)/3 + 5
2x - 2 = (x+2)/3 + 5
6x - 6 = x + 2 + 15
5x = 23
x = 23/5
The solution of x is not an integer, so this cannot happen.