SOLUTION: Find three consecutive odd integers such that the sum of the squares of the first two is 15 less than the square of the third.

SOLUTION: Find three consecutive odd integers such that the sum of the squares of the first two is 15 less than the square of the third.

Algebra.Com

Question 792830: Find three consecutive odd integers such that the sum of the squares of the first two is 15 less than the square of the third.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

(x-2)^2 + x^2 = (x+2)^2 - 15
x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 - 15
2x^2 - 4x + 4 = x^2 + 4x - 11
x^2 - 8x + 15 = 0
(x - 3)(x - 5) = 0

The integers could be (1, 3, 5) or (3, 5, 7).
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