SOLUTION: Find two consecutive natural numbers such that the difference of their reciprocals is 1/4 the reciprocal of the smallest number. translate and solve

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Question 786627: Find two consecutive natural numbers such that the difference of their reciprocals is 1/4 the reciprocal of the smallest number. translate and solve

Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
consecutive natural numbers: x, (x+1)

1/x - 1/(x+1) = 1/4x
4(x+1) - 4x = x+1
4x + 4 - 4x = x + 1
4 = x + 1
x = 3

numbers: 3, 4

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